1/2(x+1)^2-16=0

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Solution for 1/2(x+1)^2-16=0 equation: 


x in (-oo:+oo)

(1/2)*(x+1)^2-16 = 0

1/2*(x+1)^2-16 = 0

1/2*(x+1)^2-16 = 0

1/2*x^2+x-31/2 = 0

1/2*x^2+x-31/2 = 0

1/2*x^2+x-31/2 = 0

DELTA = 1^2-(-31/2*1/2*4)

DELTA = 32

DELTA > 0

x = (32^(1/2)-1)/(1/2*2) or x = (-32^(1/2)-1)/(1/2*2)

x = 4*2^(1/2)-1 or x = -4*2^(1/2)-1

(x+4*2^(1/2)+1)*(x-4*2^(1/2)+1) = 0

(x+4*2^(1/2)+1)*(x-4*2^(1/2)+1) = 0

( x+4*2^(1/2)+1 )

x+4*2^(1/2)+1 = 0 // - 4*2^(1/2)+1

x = -(4*2^(1/2)+1)

( x-4*2^(1/2)+1 )

x-4*2^(1/2)+1 = 0 // - 1-4*2^(1/2)

x = -(1-4*2^(1/2))

x in { -(4*2^(1/2)+1), -(1-4*2^(1/2)) }

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